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LTC1643ALIGN Arkusz danych(PDF) 14 Page - Linear Technology |
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LTC1643ALIGN Arkusz danych(HTML) 14 Page - Linear Technology |
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14 / 16 page ![]() 14 LTC1643AL LTC1643AL-1/LTC1643AH 1643afa R2 0.005 Ω Q2 IRF7413 Q1 IRF7413 R1 0.007 Ω R5 10 Ω R6 10 Ω R8 100k R7 100 Ω C1 0.047 µF 5V 5A 12V 1.5A 3.3V 7.6A GND R3 10k R4 10k 11 3 13 12 16 15 4 10 9 8 1 2 5 6 7 3VIN GND ON FAULT NOTE: INTENDED FOR PCI APPLICATIONS ONLY PWRGD 3VSENSE 5VSENSE 3VOUT LTC1643AH 12VOUT VEEOUT TIMER 5VIN GATE 1643A F08 SYSTEM POWER SUPPLY PCI POWER SYSTEM CONTROLLER C2 0.1 µF C3 0.1 µF R10 200 Ω R9 200 Ω Q5 TP0610T Q6 Si9410DY Q4 Si9400 Q3 TP0610T D1 1N4148 12VIN VEEIN –12V 1.5A 4 3 2 1 4 3 2 1 10 Ω Figure 8. Increasing 12V and – 12V Current Capability for PCI Applications APPLICATIONS INFORMATION Increasing 12V and – 12V Current Capability for PCI Applications The internal switches of the LTC1643A are designed for up to 500mA loads on 12V and 200mA on –12V. If more current is needed, then the circuits in Figure 8 can be used. For the 12V supply, P-channel transistor Q4 is placed in parallel with the internal switch. When the LTC1643AH is turned off, the GATE pin is held low and transistor Q3 is turned on which pulls the gate of Q4 high, turning it off. When the LTC1643AH is turned on, the GATE pin goes high, turning off Q3 and allowing R8 to pull the gate of Q4 low to turn it on. Because Q4 is in parallel with the internal 12V switch, the load current will be shared in proportion to their respective RDS(ON) values. For example, if the RDS(ON) of the external switch is 0.2 Ω and the internal switch is 0.4Ω, then, at 1.5A load current, the external switch will provide 1A and the internal switch 500mA. The circuit breaker current will be reached when the internal current reaches 1A and the external current is 2A or 3A load current. For the –12V supply, N-channel transistor Q6 is used to provide the extra load current. When the LTC1643AH is turned on, the internal VEE switch is turned on and the –12V output starts to pull down through D1 and turns on Q5. When Q5 turns on, the gate of Q6 starts to rise, turning it on. When the LTC1643AH turns off, the VEEOUT pin is pulled up to ground, diode D1 is reversed biased, and transistor Q5 turns off, which allows resistor R10 to turn off Q6. The internal –12V switch provides the current limit for the supply, but because the high RDS(ON) of the internal switch (1.2 Ω) is in series with D1, very large currents can flow through Q6 before the circuit breaker trips. However, if a short to ground occurs on the –12V output, diode D1 will prevent Q5 from turning on, which will prevent Q6 from turning on. |
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