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H5PS2G83AFR Arkusz danych(PDF) 39 Page - Hynix Semiconductor |
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H5PS2G83AFR Arkusz danych(HTML) 39 Page - Hynix Semiconductor |
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39 / 40 page ![]() Rev. 0.1 / November 2008 39 H5PS2G43AFR H5PS2G83AFR tracting 0.02 x tCK (avg) from it, whereas if an input clock has a worst case tCH (avg) of 0.52, the tAOF, max should be derated by adding 0.02 x tCK (avg) to it. Therefore, we have; tAOF, min (derated) = tAC, min - [0.5 - Min(0.5, tCH (avg), min)] x tCK (avg) tAOF, max (derated) = tAC, max + 0.6 + [Max(0.5, tCH (avg), max) - 0.5] x tCK (avg) or tAOF, min (derated) = Min (tAC, min, tAC, min - [0.5 - tCH (avg), min] x tCK (avg)) tAOF, max (derated) = 0.6 + Max (tAC, max, tAC, max + [tCH (avg), max - 0.5] x tCK (avg)) where tCH (avg), min and tCH (avg), max are the minimum and maximum of tCH (avg) actually measured at the DRAM input balls. Note that these deratings are in addition to the tAOF derating per input clock jitter, i.e. tJIT (duty) and tERR(6-10per). However tAC values used in the equations shown above are from the timing parameter table and are not derated. Thus the final derated values for tAOF are; tAOF, min (derated_final) = tAOF, min (derated) + {- tJIT (duty), max - tERR(6-10per),max} tAOF, max (derated_final) = tAOF, max (derated) + {- tJIT (duty), min - tERR(6-10per),min} |
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