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LM3578AM Arkusz danych(PDF) 18 Page - Texas Instruments

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Numer części LM3578AM
Szczegółowy opis  LM2578A/LM3578A Switching Regulator
PDF  30 Pages
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Producent  TI [Texas Instruments]
Strona internetowa  http://www.ti.com
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LM3578AM Arkusz danych(HTML) 18 Page - Texas Instruments

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LM2578A, LM3578A
SNVS767E – AUGUST 2000 – REVISED APRIL 2013
www.ti.com
Vin = 5V
R4 = 200 k
Ω
Vo = 15V
C1 = 1820 pF
Vripple = 10 mV
C2 = 470
μF
Io = 140 mA
C3 = 20 pF
fosc = 50 kHz
C4 = 0.0022
μF
R1 = 140 k
Ω
L1 = 330
μH
R2 = 10 k
Ω
D1 = 1N5818
R3 = 0.15
Ω
Figure 32. Boost or Step-Up Regulator
R1 = (Vo − 1) R2 where R2 = 10 kΩ.
R3 = V/(IL(max, DC) + 0.5 ΔIL)
where:
ΔIL = 2(ILOAD(min))(Vo/Vin)
ΔIL is 200 mA in this example.
R4, C3 and C4 are necessary for continuous operation and are typically 220 k
Ω, 20 pF, and 0.0022 μF
respectively.
C1 is the timing capacitor found in Figure 14.
C2
≥ Io (Vo − Vin)/(fosc Vo Vripple).
D1 is a Schottky type diode such as a 1N5818 or 1N5819.
L1 is found as described in the buck converter section, using the inductance chart for Figure 29 for the boost
configuration and 20% discontinuity.
INVERTING REGULATOR
Figure 33 shows the basic configuration for an inverting regulator. The input voltage is of a positive polarity, but
the output is negative. The output may be less than, equal to, or greater in magnitude than the input. The
relationship between the magnitude of the input voltage and the output voltage is Vo = Vin × (ton/toff).
Figure 33. Basic Inverting Regulator
Figure 34 shows an LM2578A configured as a 5V to
−15V polarity inverter with an output current of 300 mA, a
load regulation of 44 mV (60 mA to 300 mA) and a line regulation of 50 mV (4.5V
≤ Vin ≤ 8.5V).
18
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Product Folder Links: LM2578A LM3578A



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