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ADP1829ACPZ-R7 Arkusz danych(PDF) 21 Page - Analog Devices |
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ADP1829ACPZ-R7 Arkusz danych(HTML) 21 Page - Analog Devices |
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21 / 32 page ![]() ADP1829 Rev. 0 | Page 21 of 32 Type II Compensator G (dB) PHASE –180° –270° fZ fP 0V VRAMP CHF CI RZ RTOP RBOT FROM VOUT VREF EA COMP TO PWM –1 SLO PE –1 SLO PE Figure 28. Type II Compensation If the output capacitor ESR zero frequency is sufficiently low (≤1/2 of the crossover frequency), use the ESR to stabilize the regulator. In this case, use the circuit shown in Figure 28. Calculate the compensation resistor, RZ, with the following equation: 2 LC IN CO ESR RAMP TOP Z f V f f V R R = (31) where: fCO is chosen to be 1/10 of fSW. VRAMP is 1.3 V. Next choose the compensation capacitor to set the compensation zero, fZ1, to the lesser of 1/4 of the crossover frequency or 1/2 of the LC resonant frequency: I Z SW CO Z C R f f f π = = = 2 1 40 4 1 (32) or I Z LC Z C R f f π = = 2 1 2 1 (33) Solving for CI in Equation 32 yields SW Z I f R C π = 20 (34) Solving for CI in Equation 33 yields LC Z I f R C π = 1 (35) Use the larger value of CI from Equation 34 or Equation 35. Because of the finite output current drive of the error amplifier, CI needs to be less than 10 nF. If it is larger than 10 nF, choose a larger RTOP and recalculate RZ and CI until CI is less than 10 nF. Next choose the high frequency pole, fP1, to be 1/2 of fSW. SW P1 f f 2 1 = (36) Because CHF << CI, Equation 29 is simplified to HF Z P1 C R f π = 2 1 (37) Solving for CHF in Equation 36 and Equation 37 yields Z SW HF R f C π = 1 (38) Type III Compensator 0V VRAMP G (dB) PHASE –270° –90° fZ fP CHF CI RZ CFF RTOP RBOT FROM VOUT VREF EA COMP TO PWM RFF –1 SLO PE –1 SLO PE +1 SL OP E Figure 29. Type III Compensation If the output capacitor ESR zero frequency is greater than 1/2 of the crossover frequency, use Type III compensator as shown in Figure 29. Set the poles and zeros as follows: SW P2 P1 f f f 2 1 = = (39) I Z SW CO Z2 Z1 C R f f f f π = = = = 2 1 40 4 (40) or I Z LC Z Z C R f f f π = = = 2 1 2 2 1 (41) Use the lower zero frequency from Equation 40 or Equation 41. Calculate the compensator resistor, RZ. 2 LC IN CO Z1 RAMP TOP Z f V f f V R R = (42) Next calculate CI. Z1 Z I f R C π 2 1 = (43) |
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